Find the x-and y-intercepts of the graph of the equation algebraically. y=-\frac{1}{2}x+\frac{2}{3}

Calculation:
Consider, the equation,
${\displaystyle y=-\frac{1}{2}x+\frac{2}{3}}$
To determine x -intercept, substitute ${\displaystyle y=0}$ in the above equation,
${\displaystyle 0=-\frac{1}{2}x+\frac{2}{3}}$
${\displaystyle \frac{1}{2}x=\frac{2}{3}}$
${\displaystyle x=\frac{2}{3}\times 2}$
${\displaystyle =\frac{4}{3}}$
Therefore, the x -intercept is ${\displaystyle (\frac{4}{3},0)}$.
To determine y -intercept, substitute ${\displaystyle x=0}$ in the equation, ${\displaystyle y=-\frac{1}{2}x+\frac{2}{3}}$,
${\displaystyle y=-\frac{1}{2}\times 0+\frac{2}{3}}$
${\displaystyle =\frac{2}{3}}$
Therefore, y -intercept is ${\displaystyle (0,\frac{2}{3})}$.