Find the x-and y-intercepts of the graph of the equation algebraically. y=-\frac{1}{2}x+\frac{2}{3}

Find the x-and y-intercepts of the graph of the equation algebraically.
$y=-\frac{1}{2}x+\frac{2}{3}$
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Calculation:
Consider, the equation,
$y=-\frac{1}{2}x+\frac{2}{3}$
To determine x -intercept, substitute $y=0$ in the above equation,
$0=-\frac{1}{2}x+\frac{2}{3}$
$\frac{1}{2}x=\frac{2}{3}$
$x=\frac{2}{3}×2$
$=\frac{4}{3}$
Therefore, the x -intercept is $\left(\frac{4}{3},0\right)$.
To determine y -intercept, substitute $x=0$ in the equation, $y=-\frac{1}{2}x+\frac{2}{3}$,
$y=-\frac{1}{2}×0+\frac{2}{3}$
$=\frac{2}{3}$
Therefore, y -intercept is $\left(0,\frac{2}{3}\right)$.