Calculation:

Let the number of books be x. Since the printing and blinding cost for a college algebra cost is $10. The printing and blinding cost for 10 algebra books is 10x. The editorial cost is $200,000. The first 2500 books are free.

Thus, the average cost of sealable books is

\(\displaystyle{f{{\left({x}\right)}}}={\frac{{\to{t}{a}{l}\ {\cos{{t}}}}}{{\nu{m}{b}{e}{r}\ {o}{f}\ {s}{e}{a}{l}{a}{b}\le\ {b}\infty{k}{s}}}}\)

\(\displaystyle{f{{\left({x}\right)}}}={\frac{{{10}{x}+{200},{00}}}{{{x}-{2500}}}}\)

Hence, the required function is \(\displaystyle{f{{\left({x}\right)}}}={\frac{{{10}{x}+{200},{00}}}{{{x}-{2500}}}}\).

Let the number of books be x. Since the printing and blinding cost for a college algebra cost is $10. The printing and blinding cost for 10 algebra books is 10x. The editorial cost is $200,000. The first 2500 books are free.

Thus, the average cost of sealable books is

\(\displaystyle{f{{\left({x}\right)}}}={\frac{{\to{t}{a}{l}\ {\cos{{t}}}}}{{\nu{m}{b}{e}{r}\ {o}{f}\ {s}{e}{a}{l}{a}{b}\le\ {b}\infty{k}{s}}}}\)

\(\displaystyle{f{{\left({x}\right)}}}={\frac{{{10}{x}+{200},{00}}}{{{x}-{2500}}}}\)

Hence, the required function is \(\displaystyle{f{{\left({x}\right)}}}={\frac{{{10}{x}+{200},{00}}}{{{x}-{2500}}}}\).