To calculate: The probability that the selected student was in the 37-46 are group or received a "B" in the course. Given Information: A table depicting the grade distribution for a college algebra class based on age and grade.

texelaare 2021-03-08 Answered
To calculate: The probability that the selected student was in the 37-46 are group or received a "B" in the course.
Given Information:
A table depicting the grade distribution for a college algebra class based on age and grade.

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Expert Answer

lobeflepnoumni
Answered 2021-03-09 Author has 26012 answers
Formula used:
In a sample space, S, of equally likely, the probability of an event E is given by
\(\displaystyle{P}{\left({E}\right)}={\frac{{\nu{m}{b}{e}{r}\ {o}{f}\ {e}\le{m}{e}{n}{t}{s}\ \in\ {t}{h}{e}\ {e}{v}{e}{n}{t}}}{{\nu{m}{b}{e}{r}\ {o}{f}\ {e}\le{m}{e}{n}{t}{s}\ \in\ {t}{h}{e}\ {s}{a}\mp\le\ {s}{p}{a}{c}{e}}}}={\frac{{{n}{\left({E}\right)}}}{{{n}{\left({S}\right)}}}}\)
Calculation:
Denote the sample space as
\(\displaystyle{S}={1940}\)
Let R represent the event of selecting a student was in the 37-46 are group
\(\displaystyle{R}={370}\)
Let B represent the event of selecting a student who received a "B" in the course. Some of these students are of 37-46 age group, so
\(\displaystyle{B}={420}\)
\(\displaystyle{P}{\left({R}{\quad\text{or}\quad}{B}\right)}={\frac{{{n}{\left({R}\right)}+{n}{\left({B}\right)}}}{{{n}{\left({S}\right)}}}}={\frac{{{370}+{420}}}{{{1940}}}}={\frac{{{790}}}{{{1940}}}}={\frac{{{79}}}{{{194}}}}\)
Therefore, probability that the selected student was in the 37-46 are group or received a "B" in the course is \(\displaystyle{\frac{{{79}}}{{{194}}}}\).
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To calculate: To write the given statements (a) and (b) as functions f(x) and g(x)respectively.
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