A population of values has a normal distribution with \mu=73.1 and \sigma=28.1. You intend to draw a random sample of size n=131. Find the probability that a single randomly selected value is greater than 69.7. P(X > 69.7) =? Write your answers as numbers accurate to 4 decimal places.

EunoR 2021-02-24 Answered
A population of values has a normal distribution with μ=73.1 and σ=28.1. You intend to draw a random sample of size n=131.
Find the probability that a single randomly selected value is greater than 69.7.
P(X>69.7)=?
Write your answers as numbers accurate to 4 decimal places.
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tabuordy
Answered 2021-02-25 Author has 91 answers
Step 1
Let us denote X= population values
Given that X follows a normal distribution with mean =μ=73.1 and standard deviation =σ=28.1
Step 2
The probability that a single randomly selected value is greater than 69.7.
P(X>69.7)
=P(Z>69.773.128.1)
=P(Z0.120996441281)=0.5482
Answer: 0.5482

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