Please answer with solution.

asistioacer 2022-02-24 Answered

Please answer with solution.

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Answers (1)

alenahelenash
Answered 2022-03-10 Author has 343 answers

2. Since y=x2 and y=4xx2

x2=4xx2

2x24x=02x(x2)=0

2x=0x=0

since x=0y=x2y=0

A=(0,0)

x2=0x=2

since x=2y=x2y=4

B=(2,4)

if we take dx slice (that mean the Area revolving about x-axis)

The interval of the integral become

x[0,2]

now let set up the integral of Area

A=aby2y1dx

A=02(4xx2)(x2)dx

A=024x2x2dx=[2x223x3]02

[8163]=24163=83=2.667(unite)2

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