A population of values has a normal distribution with mean = 37.4 and standard deviation 77.4. If a random sample of size n=15 is selected, Find the probability that a single randomly selected value is greater than 53.4. Round your answer to four decimals. P(X > 53.4)=?

midtlinjeg 2021-01-22 Answered
A population of values has a normal distribution with mean = 37.4 and standard deviation 77.4. If a random sample of size n=15 is selected,
Find the probability that a single randomly selected value is greater than 53.4. Round your answer to four decimals.
P(X>53.4)=?
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wheezym
Answered 2021-01-23 Author has 103 answers

The probability that a single randomly selected value is greater than 53.4 is 0.4168, which is obtained below:
P(M>x)=1P(M<x)
=1P(z<xμσ)
P(M>53.4)=1P(M<53.4)
=1P(z<53.437.477.4)
=1P(z<0.21)[Use standard Normaltable]
=10.58317=0.4168

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