I was stuck at numbers 2 and 6. This is

Asiya Holder

Asiya Holder

Answered question

2022-02-17

I was stuck at numbers 2 and 6. This is a linear ODE.
2.(y+1)dx+(4xy)dy=0
Divided it by dx:
(y+1)+(4xy)dydx=0
Transposed the (y+1)
(4xy)dydx=(y+1)
Divided it by (4xy)
dydx=2y(x3)
The farthest I can go is:
dxdy=(2x3x2)(6y3x3).
The rest of the problems were easily solved but those 2 are very hard to bring to the standard form.

Answer & Explanation

Josef Beil

Josef Beil

Beginner2022-02-18Added 12 answers

for Nr. 2 is not linear, since it contain y*y
Kathryn Duggan

Kathryn Duggan

Beginner2022-02-19Added 7 answers

The second problem is given as
(y+1)dx+(4xy)dy=0
if you divide by dy instead of dx then you will form
(y+1)dxdy=4x+y
which simplifies to
dxdy=(4y+1)x+yy+1
or
dxdy=f(y)x+g(y)
which is a first-order linear ordinary differential equation.
The sixth problem is given as
3xdxdy=2y(x3)
where rearranging leads to
12ydy=x33xdx
or
12ydy=(131x)dx
which can be solved by techniques which are known to you.

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