A distribution of values is normal with a mean of 79.5 and a standard deviation of 7.4.Find the probability that a randomly selected value is between 71.4 and 78.P(71.4 < x < 78) = P( < z < ) =?

allhvasstH 2021-01-19 Answered

A distribution of values is normal with a mean of 79.5 and a standard deviation of 7.4.
Find the probability that a randomly selected value is between 71.4 and 78.
P(71.4<x<78)=P(<z<)=?

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Expert Answer

bahaistag
Answered 2021-01-20 Author has 101 answers

Step 1:
A distribution of values is normal
Mean = 79.5
Standard deviation = 7.4
Step 2: Probability is given by,
The probability that a randomly selected value is between 71.4 and 78 is given by,
P(71.4<X<78)=P(71.479.57.4<xμσ<7879.57.4)
P(71.4<X<78)=P(1.09<Z<0.20)
P(71.4<X<78)=0.2828
By using Standard normal table.

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Jeffrey Jordon
Answered 2021-11-17 Author has 2087 answers

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