For f(x)=4x^{3}+12x^{2}+9x+7, what is the equation of the line tangent

Potherat8mi

Potherat8mi

Answered question

2022-02-15

For f(x)=4x3+12x2+9x+7, what is the equation of the line tangent to x=32?

Answer & Explanation

Jett Brooks

Jett Brooks

Beginner2022-02-16Added 7 answers

mtangent=f(x) at x=32
f(x)=12x2+24x+9
f(32)=12(32)2+24(32)+9=0
tangent is parallel to the x-axis
f(32)=4(32)3+12(32)2+9(32)+7
=7
equation of tangent is y=7

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