How do you write an equation of the line tangent

Lubna Boyce

Lubna Boyce

Answered question

2022-02-18

How do you write an equation of the line tangent to the graph of f(x)=715x+9x2x3 at x=2?

Answer & Explanation

legertopdxa

legertopdxa

Beginner2022-02-19Added 8 answers

f(x)=715x+9x2x3 evaluate f(2):
f(2)=7152+92223
f(2)=730+368=5 tangent at point: (2,5)
The slope of the tangent line to graph of a function at a point is equal to first derivative of the function evaluated at that point:
f(x)=15+18x3x2=3(x26x+5)
f'(2)=-3(4-12+5)=9
Slope = m = 9, point (x1,y1)=(2,5), using point-slope form:
yy1=m(xx1):
y5=9(x2) equation of tangent in point-slope form
y=9x13 equation of tangent in slope-intercept form

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