A population of values has a normal distribution with \mu = 49 and \sigma = 79.5. You intend to draw a random sample of size n=84. Find the probability that a single randomly selected value is greater than 72.4. P(X>72.4)=? Write your answers as numbers accurate to 4 decimal places.

waigaK 2020-11-02 Answered
A population of values has a normal distribution with μ=49 and σ=79.5. You intend to draw a random sample of size n=84.
Find the probability that a single randomly selected value is greater than 72.4.
P(X>72.4)=?
Write your answers as numbers accurate to 4 decimal places.
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Expert Answer

SoosteethicU
Answered 2020-11-03 Author has 102 answers

Step 1
Given,
Mean =49
Standard deviation =79.5
Sample size =84
Step 2
Consider,
P(X>72.4)=P(Xμσ>72.4μσ)
=P(Z>72.44979.5)
=P(Z>0.294)
=1P(Z0.294)
=10.6156=0.3844 (From the standard normal table)
The probability that a single randomly selected value is greater than 72.4 is, 0.3844.

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Jeffrey Jordon
Answered 2021-11-17 Author has 2262 answers

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