A population of values has a normal distribution with \mu = 49 and \sigma = 79.5. You intend to draw a random sample of size n=84. Find the probability that a single randomly selected value is greater than 72.4. P(X>72.4)=? Write your answers as numbers accurate to 4 decimal places.

waigaK

waigaK

Answered question

2020-11-02

A population of values has a normal distribution with μ=49 and σ=79.5. You intend to draw a random sample of size n=84.
Find the probability that a single randomly selected value is greater than 72.4.
P(X>72.4)=?
Write your answers as numbers accurate to 4 decimal places.

Answer & Explanation

SoosteethicU

SoosteethicU

Skilled2020-11-03Added 102 answers

Step 1
Given,
Mean =49
Standard deviation =79.5
Sample size =84
Step 2
Consider,
P(X>72.4)=P(Xμσ>72.4μσ)
=P(Z>72.44979.5)
=P(Z>0.294)
=1P(Z0.294)
=10.6156=0.3844 (From the standard normal table)
The probability that a single randomly selected value is greater than 72.4 is, 0.3844.

Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-17Added 2605 answers

Answer is given below (on video)

Do you have a similar question?

Recalculate according to your conditions!

New Questions in College Statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?