Let X \sim N(6,4).Find the probabilities P(X<3).

Anish Buchanan

Anish Buchanan

Answered question

2021-01-31

Let XN(6,4).Find the probabilities P(X<3).

Answer & Explanation

davonliefI

davonliefI

Skilled2021-02-01Added 79 answers

Step 1
Introduction:
The normal probability is a type of continuous probability distribution that can take random values. The normal distribution is determined by the two parameters - the population mean (μ) and population variance (σ2). It is symmetric with respect to its mean.
Given information:
XN(6,4)
Therefore,
μ=6
σ2=4

Step 2
P(X<3) is computed as follows:
P(X<3)=P(Xμσ2<3μσ2)
=P(Z<364)
=P(Z<1.5)
=1P(Z<1.5)
=10.93319=0.06681
Therefore,
P(X<3)=0.0668

Do you have a similar question?

Recalculate according to your conditions!

New Questions in College Statistics

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?