Let X \sim N(6,4).Find the probabilities P(X>8).

nicekikah

nicekikah

Answered question

2021-02-25

Let XN(6,4).Find the probabilities P(X>8).

Answer & Explanation

hosentak

hosentak

Skilled2021-02-26Added 100 answers

Step 1
Introduction:
The normal probability is a type of continuous probability distribution that can take random values. The normal distribution is determined by the two parameters - the population mean (μ) and population variance (σ2). It is symmetric with respect to its mean.
Given information:
XN(6,4)
Therefore,
μ=6
σ2=4
Step 2
P(X>8) is computed as follows:
P(X>8)=P(Xμσ2>8μσ2)
=P(Z>864)
=P(Z>1)
=1P(Z1)
=10.84134=0.15866
Therefore,
P(X>8)=0.1587

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