# A population of values has a normal distribution with \mu=77 and \sigma=32.2.

A population of values has a normal distribution with $\mu =77$ and $\sigma =32.2$. You intend to draw a random sample of size $n=15$
Find the probability that a single randomly selected value is between 59.5 and 98.6. $P\left(59.5?

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SoosteethicU

From the given information, $\mu =77$, $\sigma =32.2$ and the sample size=15.
Consider,
$P\left(59.5
$=P\left(\frac{59.5-77}{32.2}
$=P\left(-0.54348
$=P\left(z<0.6770807\right)-P\left(z<-0.54348\right)$

Thus, the probability that a single randomly selected value is between 59.5 and 98.6 is 0.4554.

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Jeffrey Jordon

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