A box contains 11 marbles, 7 red, and 4 green.

fumefluosault7pa

fumefluosault7pa

Answered question

2022-02-12

A box contains 11 marbles, 7 red, and 4 green. Five of these marbles are removed at random. If the probability of drawing a green marble is now 0.5, how many red marbles were removed?

Answer & Explanation

Finn Lucero

Finn Lucero

Beginner2022-02-13Added 17 answers

Given:
Red marbles =7
Green marbles =4
Total no of marbles =11
Number of Marbles removed =5
Marbles in the box =115=6
Probability of drawing one green marble is =0.5
Among the remaining 6 marbles, x number of marbles are green.
Then Probability of drawing one green marble is = number of green marbles / Total Number of marbles.
P1 green=x6
We know P1 Green=0.5
Then
x6=0.5
x=0.5×6=3
After 5 marbles are removed from the box, the number of green marbles remaining is 3.
It means out of 4 green marbles, one green marble has been removed.
Out of 5 marbles one marble is green. Then the other four must be red.
Then number of red marbles removed were =4.

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