A box contains 11 marbles, 7 red, and 4 green.

fumefluosault7pa 2022-02-12 Answered
A box contains 11 marbles, 7 red, and 4 green. Five of these marbles are removed at random. If the probability of drawing a green marble is now 0.5, how many red marbles were removed?
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Expert Answer

Finn Lucero
Answered 2022-02-13 Author has 17 answers
Given:
Red marbles =7
Green marbles =4
Total no of marbles =11
Number of Marbles removed =5
Marbles in the box =115=6
Probability of drawing one green marble is =0.5
Among the remaining 6 marbles, x number of marbles are green.
Then Probability of drawing one green marble is = number of green marbles / Total Number of marbles.
P1 green=x6
We know P1 Green=0.5
Then
x6=0.5
x=0.5×6=3
After 5 marbles are removed from the box, the number of green marbles remaining is 3.
It means out of 4 green marbles, one green marble has been removed.
Out of 5 marbles one marble is green. Then the other four must be red.
Then number of red marbles removed were =4.
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