A population of values has a normal distribution with \mu=226.7 and \sigma=59.8. If a random sample size of n=24 is selected. Find the probability that a single randomly selected value is greater than 192.5.

FobelloE 2021-03-02 Answered
A population of values has a normal distribution with μ=226.7andσ=59.8. If a random sample size of n=24 is selected.
Find the probability that a single randomly selected value is greater than 192.5.
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Expert Answer

Laaibah Pitt
Answered 2021-03-03 Author has 98 answers

Let X follows N(μ=226.7.σ=59.8)
The probability that a single randomly selected value is greater than 192.5 is,
P(X>192.5)=1P(X192.5)
=1P(Xμσ204512)
=1P(z0.57)
=1(=NORMDIST(0.57)) (Using the excel fromula)
=10.2843=0.7157
Therefore, the required probability is, 0.7157.

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