How do you show that the point (p, 4p^{2}) lies

kaliitcri

kaliitcri

Answered question

2022-02-13

How do you show that the point (p,4p2) lies on the curve y=4x2 for all real values of p and then find the equation of the tangent to y=4x2 at (p,4p2)?

Answer & Explanation

Bryce Barry

Bryce Barry

Beginner2022-02-14Added 12 answers

You can substitute the coordinate x=p of your point into the function to get:
y=4p2 so your point does lie on the curve represented by y=4x2.
Your function is a quadratic which can accept all real values of x so that p can be every real value.
Deriving your function you get the slope of the tangent to the curve at a generic x:
y=8

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?