How do you find the product (2a-9)(3a^{2}+4a-4)?

Edkowiez2x

Edkowiez2x

Answered question

2022-02-10

How do you find the product (2a9)(3a2+4a4)?

Answer & Explanation

Johnathan Carpenter

Johnathan Carpenter

Beginner2022-02-11Added 12 answers

(2a9)(3a2+4a4)
=2a(3a2+4a4)9(3a2+4a4)
=(6a3+8a28a)(27a2+36a36)
=6a3+8a28a27a236a+36
=6a3+8a227a28a36a+36
=6a319a244a+36
Pecsan9mj

Pecsan9mj

Beginner2022-02-12Added 13 answers

To find the product you have to multiply each term in the one parenthesis with each term in the second parenthesis and add together.
In this instance you will first multiply all the terms in (3a2+4a4) with 2a, there after all the terms in (3a2+4a4) with 9 and then add together
1. (3a2+4a4)2a=6a3+8a28a
2. (3a2+4a4)9=27a2+36a36
But as 9 is negative, "adding together" implies that the 2nd expression must be subtracted from the 1st:
(6a3+8a28a)(27a2+36a36)
=6a3+(827)a2(8+36)a+36
(remember that -(-36)=+36)
=6a319a244a+36

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