Given Information:

\(\displaystyle\mu={129.7}\)

\(\displaystyle\sigma={7.7}\)

\(\displaystyle{n}={10}\)

Step 2

The probability that a single randomly selected value is less than 130.9

Firstly, z score will be determined.

\(\displaystyle{z}={\frac{{{x}-\mu}}{{\sigma}}}={\frac{{{130.9}-{129.7}}}{{{7.7}}}}={0.155}\)

By referring to the z distribution, the p-value at \(\displaystyle{z}={0}\).155 is 0.438

Therefore, the probability that a single randomly selected value is less than 130.9 is 0.438