# Solve the absolute value equation.-7(y + 5) < -9y - 35

Solve the absolute value equation.
$-7\left(y+5\right)<-9y-35$

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berggansS

Step 1
Solve the absolute value function as follows.
$-7\left(y+5\right)<-9y-35$
$-7\cdot y+\left(-7\right)\cdot 5<-9y-35$ (Multiply -7 inside the paranth eses)
$-7y-35<-9y-35$
$-7y-35+35<-9y-35+35$ (Add 35 to both sides)
$-7y<-9y$
Step 2
On further simplification.
$-7y+9y<-9y+9y$ (Add 9y to both sides)
$2y<0$
$\frac{2y}{2}<\frac{0}{2}$ (Divide the inequality by 2 on both sides)
$y<0$
Step 3
Result:
The solution set of the absolute value function is $\left\{y\mid y<0\right\}$ or using interval notation, $\left(-\propto ,0\right)$.

Jeffrey Jordon