How do you multiply (2m^{2}+n)(3n^{2}+6mn-m^{2})?

rockingmydfhz

rockingmydfhz

Answered question

2022-02-10

How do you multiply (2m2+n)(3n2+6mnm2)?

Answer & Explanation

Keely House

Keely House

Beginner2022-02-11Added 13 answers

We use the distributive property of multiplication.
(2m2+n)(3n2+6mnm2)=2m2(3n2+6mnm2)+n(3n2+6mnm2)
=(6m2n2+12m3n2m4)+(3n3+6mn2m2n)
Now we remove parentheses and arrange the terms in descending powers of m and ascending powers of n.
(2m2+n)(3n2+6mnm2)=2m4+12m3n+6m2n2m2n+6mn2+3n3

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