How do you multiply (3u^{2}-n)^{2}?

Tucker Lewis

Tucker Lewis

Answered question

2022-02-10

How do you multiply (3u2n)2?

Answer & Explanation

tacalaohn

tacalaohn

Beginner2022-02-11Added 13 answers

Explanation:
(3u2n)(3u2n)
9u43u2n3u2n+n2
9u46u2+n2
ithangesf4

ithangesf4

Beginner2022-02-12Added 16 answers

To expand (3u2n)2 you can use the FOIL method. That stands for:
Fist
Outer
Inner
Last
In essence, you just want to multiply all combinations of the two brackets.
Since (3u2n) is squared, you can rewrite (3u2n)2=(3u2n)(3u2n)
Now you use the FOIL method to expand. "First" means you multiply the first term of the first bracket by the first term in the second bracket
3u23u2=9u4
"Outer" means you multiply the first term in the first bracket by the last term in the second bracket- they are the outermost terms
3u2
n=3ν2
"Inner" means you multiply the second term of the first bracket with the first term in the second bracket
n3u2=3ν2
"Last" means you mutiply the last terms of each bracket
nn=n2
Now you combine everything:
(3u2n)2=(3u2n)(3u2n)=9u43ν23ν2+n2=9u46ν2+n2

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