# Solve the absolute value inequality 2|3x + 9| < 36.

Solve the absolute value inequality $2|3x+9|<36$.

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$2\frac{|3x+9|}{2}<\frac{36}{2}$
$⇒|3x+9|<18$
$⇒-18<3x+9<18$
Subtracting 9 from both sides,
$⇒-18-9<3x+9-9<18-9$
$⇒-27<3x<9$
Dividing both side by 3,
$⇒-\frac{27}{3}<\frac{3x}{3}<\frac{9}{3}$
$⇒-9