The area of a particular triangle can be represented by $x}^{2}+\frac{3}{2}x-\frac{9}{2$ .

What are its base and height in terms of x?

What are its base and height in terms of x?

Rinoslirl9h1
2022-02-10
Answered

The area of a particular triangle can be represented by $x}^{2}+\frac{3}{2}x-\frac{9}{2$ .

What are its base and height in terms of x?

What are its base and height in terms of x?

You can still ask an expert for help

hotlegsaprile2u

Answered 2022-02-11
Author has **21** answers

The area of a triangle is $=\frac{1}{2}\cdot b\cdot h$

so,

$\frac{1}{2}\cdot b\cdot h={x}^{2}+\frac{3}{2}x-\frac{9}{2}$

$b\cdot h=2{x}^{2}+3x-9$

=(2x-3)(x+3)

Therefore,

b=(2x-3)

h=(x+3)

or inversely

The answer is (2x-3) and (x+3)

so,

=(2x-3)(x+3)

Therefore,

b=(2x-3)

h=(x+3)

or inversely

The answer is (2x-3) and (x+3)

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