How do you solve for x?: \log_{3}(x-2)+\log_{3}(x-4)=2

m1cadc

m1cadc

Answered question

2022-02-04

How do you solve for x?:
log3(x2)+log3(x4)=2

Answer & Explanation

Kristian Willis

Kristian Willis

Beginner2022-02-05Added 6 answers

Step 1
We can combine the two logs as:
log3[(x2)(x4)]=2
Use the definition of log to get:
(x2)(x4)=32
x24x2x+8=9
x26x1=0
x1, 2=6±36+42
two solutions:
x1=6.1623
x2=0.1623 No

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