How do you solve for x? \log_{2}(2^{x+3})=15?

Ella Moon

Ella Moon

Answered question

2022-02-06

How do you solve for x?
log2(2x+3)=15?

Answer & Explanation

Pecsan9mj

Pecsan9mj

Beginner2022-02-07Added 13 answers

Step 1
log2(2x+3)=15 if loga(x)=yx=ay, so:
2x+3=215 when the same bases to different exponents are
equal then the exponents must be equal, then:
x+3=15 subtract 3 from both sides:
x=12

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