The graph of g consists of two straight lines and a semicircle. Use it to eveluate the integral.

Albarellak
2021-02-05
Answered

The graph of g consists of two straight lines and a semicircle. Use it to eveluate the integral.

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Aniqa O'Neill

Answered 2021-02-06
Author has **100** answers

The integral

We note that this area forms a semicircle with radius r = 10. Since the semicricle lies below the horizontal axis, the integral will be negative.

The area of a circle is the product of

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How Can you factor 1/2 out of integral of $\mathrm{cos}2x$ ?

$\int \mathrm{cos}2xdx$

simplifies to

$\frac{1}{2}\int \mathrm{cos}udu$

where u=2x

My Question is where does the$\frac{1}{2}$ that is factored out come from?

It would make more sense for a factor of 1/2 to be extracted if the integral was:

$\int \frac{\mathrm{cos}x}{2}dx$

simplifies to

where u=2x

My Question is where does the

It would make more sense for a factor of 1/2 to be extracted if the integral was:

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The graph of g consists of two straight lines and a semicircle. Use it to eveluate the integral.