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# Solve the set of congruences 2x -= 1(mod 5) x -= 3(mod 4) # Solve the set of congruences 2x -= 1(mod 5) x -= 3(mod 4)

Question
Congruence asked 2021-03-07
Solve the set of congruences
$$\displaystyle{2}{x}\equiv{1}{\left(\text{mod}{5}\right)}$$
$$\displaystyle{x}\equiv{3}{\left(\text{mod}{4}\right)}$$

## Answers (1) 2021-03-08
Step 1
Here, we have to solve for congruences
2x=1 mod 5
x=3 mod 4
To solve such questions, we apply chinese remainder theorem.
Chinese Remainder Theorem- Let m, n are relatively prime integers. Then the system of simultaneous congruences $$\displaystyle{x}\equiv{a}_{{1}}{\left(\text{mod}{m}\right)}{x}\equiv{a}_{{2}}{\left(\text{mod}{n}\right)}$$ has a unique solution modulo M = mxn, for any given integers $$\displaystyle{a}_{{1}},{a}_{{2}}$$.
Step 2
$$\displaystyle{2}{x}={1}\text{mod}{5}\Rightarrow{2}\times{3}={3}\text{mod}{5}\Rightarrow{x}={3}\text{mod}{5}$$
and we have x = 3 mod 4
Here, 4 and 5 are co-prime, therefore By chinese remainder theorem, it has unique solution module 20.
So, only possibilty is x=23 which satisfy the given congruences.
Step 3
Answer:
x=23

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