# Find the smallest positive integer x that solves the congruence: 7x -= 5 (mod52)

Find the smallest positive integer x that solves the congruence:
$7x\equiv 5\left(\text{mod}52\right)$
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Step 1
$7x\equiv 5\left(\text{mod}52\right)$...(1)
5 (mod52) is essentially modules division.
To discover 5 mod 52 utilizing the Modulo Method, we first separation the Dividend (5) by the Divisor (52).
Second, we increase the Whole piece of the Quotient in the past advance by the Divisor (52).
At that point at long last, we take away the appropriate response in the second step from the Dividend (5) to find the solution. Here is the math to represent how to get 5 mod 52 utilizing our
Modulo Method:
$\frac{5}{52}=0.096154$
$0×52=0$
5-0=5
Subsequently, 5 (mod52) is 5.
Step 2
Hence using equation (1)
7x=5
and $x=\frac{5}{7}=0.7$
Hence x = 0.7