Find the smallest positive integer x that solves the congruence: 7x -= 5 (mod52)

Find the smallest positive integer x that solves the congruence:
$7x\equiv 5\left(\text{mod}52\right)$
You can still ask an expert for help

Want to know more about Congruence?

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

saiyansruleA
Step 1
$7x\equiv 5\left(\text{mod}52\right)$...(1)
5 (mod52) is essentially modules division.
To discover 5 mod 52 utilizing the Modulo Method, we first separation the Dividend (5) by the Divisor (52).
Second, we increase the Whole piece of the Quotient in the past advance by the Divisor (52).
At that point at long last, we take away the appropriate response in the second step from the Dividend (5) to find the solution. Here is the math to represent how to get 5 mod 52 utilizing our
Modulo Method:
$\frac{5}{52}=0.096154$
$0×52=0$
5-0=5
Subsequently, 5 (mod52) is 5.
Step 2
Hence using equation (1)
7x=5
and $x=\frac{5}{7}=0.7$
Hence x = 0.7