What is the standard form of y=(2x+14)(x+12)-(7x-7)^{2}?

Founuwqt

Founuwqt

Answered question

2022-02-02

What is the standard form of y=(2x+14)(x+12)(7x7)2?

Answer & Explanation

Rachel Frazier

Rachel Frazier

Beginner2022-02-03Added 14 answers

Explanation:
y=(2x+14)(x+12)(7x7)2
y=2x3+24x+14x+168(49x298x+49)
y=2x2+24x+14x+16849x2+98x49
y=47x2+136x+119
Result:
y=47x2+136x+119
iloverayyeb

iloverayyeb

Beginner2022-02-04Added 14 answers

Explanation:
The equation of a quadratic in standard form is: y=ax2+bx+c
So, this question is asking us to find a,b,c
y=(2x+14)(x+12)(7x7)2
It is probably simplier to break y in its two parts first.
y=y1y2
Where: y1=(2x+14)(x+12) and y2=(7x7)2
Now, expand y1
y1=2x2+24x+14x+168
=2x2+38x+168
Now, expand y2
y2=(7x7)2=72(x1)2
=49(x22x+1)
=49x298x+49
We can now simply combine y1y2 to form y
Thus, y=2x2+38x+168(49x298x+49)
=2x2+38x+16849x2+98x49
Combine coefficients of like terms.
y=(249)x2+(38+98)x+(16849)
y=47x2+136x+119 (Is our quadratic in standard form)
a=-47, b=+136, c=+119

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