How do you simplify i6(2i−i2−3i3)?

Question

intacte87 · Accepted Answer

Solution:&amp;nbsp;Expand expressioni6(2i−i2−3i3)=2i7−i8−3i9&amp;nbsp;But we are conscious of:i1=i&amp;nbsp;i2=−1&amp;nbsp;(by definition)&amp;nbsp;i3=i2⋅i=−i&amp;nbsp;i4=i2⋅i2=(−1)⋅(−1)=1&amp;nbsp;i5=i4⋅i=1⋅i=i&amp;nbsp;and starts again&amp;nbsp;i6=i5⋅i=i⋅i=i2=−1&amp;nbsp;i7=i6⋅i=−i&amp;nbsp;To get this click-through result, type:i6(2i−i2−3i3)=2i7−i8−3i9=−2i−1−3i=−1−5i

Jillian Edgerton · Accepted Answer

We factorize powers of &quot;i&quot; first. So&amp;nbsp;i6&amp;nbsp;would become&amp;nbsp;01.3i3&amp;nbsp;would become -3i and&amp;nbsp;i2&amp;nbsp;would become -1.By putting values&amp;nbsp;−1(2i−(−1)+3i). Now&amp;nbsp;−1(2i+3i+1)&amp;nbsp;would become&amp;nbsp;−1(5i+1)&amp;nbsp;and then&amp;nbsp;−5i−1

alenahelenash · Accepted Answer

i6(2i−i2−3i3)=2i7−i8−3i9 i1=i i2=−1 i3=i2⋅i=−i i4=i2⋅i2=(−1)⋅(−1)=1 i5=i4⋅i=1⋅i=i i6=i5⋅i=i⋅i=i2=−1 i7=i6⋅i=−i i6(2i−i2−3i3)=2i7−i8−3i9=−2i−1−3i=−1−5i

How do you simplify i^{6}(2i-i^{2}-3i^{3})?

Answered question

Answer & Explanation

New Questions in Precalculus