How do you find the square root of 16(\cos60^{\circ}+i\sin60^{\circ})?

GrareeCowui

GrareeCowui

Answered question

2022-01-31

How do you find the square root of 16(cos60+isin60)?

Answer & Explanation

waijazar1

waijazar1

Beginner2022-02-01Added 13 answers

Step 1
z=16(cos60+isin60)
z=z12=16(cos60+isin60)
z12=4(cos60+isin60)12
now using DeMoivres

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