To prove:The congruency of vec(MH) ~= vec(JO). Given information: The following information has been given GJKM is a rhombus /_JOG=/_MHG=90^(circ)

Formula used : By the virtue of similarity, if any two angles of the triangles are congruent, the third one will also be congruent
Proof : In triangles JOG and MHG,
${\displaystyle \mathrm{\angle }G}$ is common angle
${\displaystyle \overrightarrow{MJ}\stackrel{\sim }{=}\overrightarrow{GJ}}$ (Rhombus)
${\displaystyle \mathrm{\angle }JOG=\mathrm{\angle }MHG={90}^{\circ }}$
Thus, using virtue of similarity, we know that triangles JOG ang MHG are similar triangles.
Now,
${\displaystyle \mathrm{\angle }G}$ is common angle
Thus, we know that
${\displaystyle \mathrm{△}JOG\stackrel{\sim }{=}\mathrm{△}MHG}$
Hence, by virtue of congruency, ${\displaystyle \overrightarrow{MH}\stackrel{\sim }{=}\overrightarrow{JO}}$