To determine:To Find:the measure of side BB' in the figure shown such that VA' = 15, A'A=20 and A'B'=24 Given: Figure is shown below. 12210202971.jpg

Question

To determine:To Find:the measure of side BB

Answer 1

Calculation:
Since, plane of

△ A^{'} B^{'} C^{'}

is similar to the plane of

△ A B C

Since, ABCD is a parallelogram.

∠ V = ∠ V ∴

(Common)

∠ V A B = ∠ V A^{'} B^{'} ∴

(Corresponding angle in two similar plane)
Therefore by AA similarity,

△ V A B \sim △ V A^{'} B^{'}

Ratio of corresponding sides in two similar triangles is equal.

\frac{V A}{V A^{'}} = \frac{V C}{V C^{'}}

\frac{V A^{'} + \forall^{'}}{V A^{'}} = \frac{A B}{A^{'} B^{'}}

\frac{15 + 20}{15} = \frac{V C}{24}

A B = \frac{24 \times 35}{15}

AB=56
Therefore, the answer is 56.

Expert Answer