Josalynn
2021-02-25
Answered

Provide the formula for mean all symbols.

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liingliing8

Answered 2021-02-26
Author has **95** answers

It is known that, mean is the average value of a set of observation.

Assume a set of random variables X for size N, as${X}_{1},{X}_{2},.....{X}_{n}$ .

Now, the mean of the set of random variables is defined as,

$M=\frac{\sum x}{n}$ where M is he mean,sum X defines the sum of all random variables of size N and N is the size of the set of random variables.

Assume a set of random variables X for size N, as

Now, the mean of the set of random variables is defined as,

asked 2021-02-21

We wish to estimate what percent of adult residents in a certain county are parents. Out of 600 adult residents sampled, 192 had kids. Based on this, plot a

Express your answer in the form of three inequalities. Give your answers in decimal fractions up to three places

asked 2021-03-18

A population of values has a normal distribution with

Find the probability that a single randomly selected value is between 133.6 and 134.1.

Write your answers as numbers accurate to 4 decimal places.

asked 2022-03-08

You are conducting a multinomial hypothesis test for the claim that all 5 categories are equally likely to be selected. Complete the table.

$\begin{array}{|cccc|}\hline \text{Category}& \text{Observed Frequency}& \text{Expected Frequency}& \text{Squared Pearson Residual}\\ \text{A}& 18\\ \text{B}& 10\\ \text{C}& 15\\ \text{D}& 17\\ \text{E}& 17\\ \hline\end{array}$

What is the chi-square test-statistic for this data?

${\chi}^{2}=$

Report all answers accurate to three decimal places.

What is the chi-square test-statistic for this data?

Report all answers accurate to three decimal places.

asked 2021-02-08

A population of values has a normal distribution with $\mu =73.1$ and $\sigma =28.1$ . You intend to draw a random sample of size $n=131$ .

Find the probability that a sample of size$n=131$ is randomly selected with a mean greater than 69.7.

$P\left(M>69.7\right)=$ ?

Write your answers as numbers accurate to 4 decimal places.

Find the probability that a sample of size

Write your answers as numbers accurate to 4 decimal places.

asked 2021-08-08

Survey A asked 1000 people how they liked the new movie Avengers: Endgame and $88\mathrm{\%}$ said they did enjoy it.

Survey B also concluded that$82\mathrm{\%}$ of people liked the move but they asked 1600 total moviegoers.

Which of the following is true about this comparison?

The margin of error is the same for both.

The confidence interval is smaller for Survey B.

Increasing the number of people asked does not change the$95\mathrm{\%}$ confidence interval.

Survey A is more accurate since the percentage is higher.

Survey A has more approvals than Survey B.

Survey A is better than Survey B since it has a higher percentage.

Survey B also concluded that

Which of the following is true about this comparison?

The margin of error is the same for both.

The confidence interval is smaller for Survey B.

Increasing the number of people asked does not change the

Survey A is more accurate since the percentage is higher.

Survey A has more approvals than Survey B.

Survey A is better than Survey B since it has a higher percentage.

asked 2021-01-08

The two-way table below describes the members of the U.S Senate in a recent year.

If we select a U.S. senator at random, what's the probability that the senator is a Democrat?

asked 2021-10-17

Reporting summary measures such as the mean, median, and standard deviation has become very common in modern life. Many companies, government agencies will report these descriptive measures of a variable, but they will rarely provide information on the shape of the distribution of that variable. In previous tutorials, you have learned some basic properties of some distributions that can help you to decide if a specific type of distribution is a good fit for a set of data.

According to the National Diet and Nutrition Survey: Adults Aged 19 to 64, British men spend an average of 2.15 hours per day in moderate or high intensity physical activity. The standard deviation of these activity times for this sample was 3.59 hours. Can we infer that these activity times could follow a normal distribution? The following may provide an answer.

Suppose that the standard deviation for this sample was 0.70 hours instead of 3.59 hours, which make it numerically possible for the distribution to be normal. Again, considering the variable being measured, explain why the normal distribution is still not a logical choice for this distribution.

According to the National Diet and Nutrition Survey: Adults Aged 19 to 64, British men spend an average of 2.15 hours per day in moderate or high intensity physical activity. The standard deviation of these activity times for this sample was 3.59 hours. Can we infer that these activity times could follow a normal distribution? The following may provide an answer.

Suppose that the standard deviation for this sample was 0.70 hours instead of 3.59 hours, which make it numerically possible for the distribution to be normal. Again, considering the variable being measured, explain why the normal distribution is still not a logical choice for this distribution.