meteraiqn
2022-01-28
Answered

How do you find the variance of the data 2, 4, 6, 8, 10?

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sainareon2

Answered 2022-01-29
Author has **10** answers

Explanation:

Variance$\left({\sigma}^{2}\right)$ is the average of squared difference from mean.

Mean is$M=\frac{2+4+6+8+10}{5}=\frac{30}{5}=6$

Variance is$\sigma}^{2}=\frac{{(2-6)}^{2}+{(4-6)}^{2}+{(6-6)}^{2}+{(8-6)}^{2}+{(10-6)}^{2}}{5$

$=\frac{16+4+0+16+4}{5}=\frac{40}{5}=8$

So the variance is 8 [Ans]

Variance

Mean is

Variance is

So the variance is 8 [Ans]

search633504

Answered 2022-01-30
Author has **16** answers

Mean, $\stackrel{\u2015}{x}=\frac{2+4+6+8+10}{5}=\frac{30}{5}=6$

$\therefore$ Variance $=\frac{1}{n}\sum {({x}_{i}-\stackrel{\u2015}{x})}^{2}$

$=\frac{1}{5}\le ft\{{(2-6)}^{2}+{(4-6)}^{2}+{(6-6)}^{2}+{(8-6)}^{2}+{(10-6)}^{2}right\}$

$=\frac{1}{5}\le ft\{16+4+0+4+16right\}=\frac{1}{5}\times 40=8$

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