the relation f^2+g^2=1 is followed only by trigonometric functions for differentiable function

Nylah Church

Nylah Church

Answered question

2022-01-28

the relation f2+g2=1 is followed only by trigonometric functions for differentiable functions
Let UC be an open, convex and connected subset and let f,g:UC be two differentiable functions so that f,g are continuous functions f(,gC1)
I want to show that if f2+g2=1 over U then there is a function z:UC such that f(t)=sin(z(t))  and  g(t)=cos(z(t))

Answer & Explanation

Mazzuranavf

Mazzuranavf

Beginner2022-01-29Added 10 answers

Note that f2+g2=1(f+ig)(fig)=1. In particular, f+ig has no zeros. So, there's a function h such that f+ig=exph. Besides
fig=1f+ig=1exph=exp(h)
Therefore,
f=f+ig+fig2=exph+exp(h)2
and
g=f+ig(fig)2i=exphexp(h)2i
So, take z=ih(h=iz)

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