# Show the following simultaneous equations in matrix form:4x-4y-6=016y=14x+4

Question
Algebra II

Show the following simultaneous equations in matrix form:
$$4x-4y-6=0$$
$$16y=14x+4$$

2021-03-07

Given simultaneous equations are
$$4x−4y−6=0$$
$$16y=14x+4$$
The given equations can be re-arranged as
$$4x−4y−=6(I)$$
$$-14x+16y=4(II)$$
Let us consider the matrix A formed with co-efficients of the given equations. Then,
$$A=((4,-4),(-14,16))$$
Let,
$$X=((x),(y))$$
$$b=((6),(4))$$
The the given system of simultaneous equations can be written in matrix form as
$$Ax=b (III)$$

### Relevant Questions

Let B be a $$(4\times3)(4\times3)$$ matrix in reduced echelon form.

a) If B has three nonzero rows, then determine the form of B.

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Demonstrate that the system of equations is inconsistent.

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$$2x+4y=10$$
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Find the solution to the system of equations.
A. (0, -3)
B. (-6, 0)
C. There are infinite solutions.
D. There are no solutions.

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$$3x+7y-20z=-4$$
$$5x+12y-34z=-7$$

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