Given simultaneous equations are

\(4x−4y−6=0\)

\(16y=14x+4\)

The given equations can be re-arranged as

\(4x−4y−=6(I)\)

\(-14x+16y=4(II)\)

Let us consider the matrix A formed with co-efficients of the given equations. Then,

\(A=((4,-4),(-14,16))\)

Let,

\(X=((x),(y))\)

\(b=((6),(4))\)

The the given system of simultaneous equations can be written in matrix form as

\(Ax=b (III)\)