Find an LU factorization of A = [(h,-4,-2,10),(h,-9,4,2),(0,0,-4,2),(0,1,4,4),(0,0,0,h/2)]. h=102

Rui Baldwin 2021-02-13 Answered
Find an LU factorization of A=[h4210h94200420144000h2].
h=102
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Expert Answer

yagombyeR
Answered 2021-02-14 Author has 92 answers
Step 1
A=[10242101029420042014400051]
In this problem, we have to find matrices L(lower triangular) and U(upper triangular) for which A=LU
Initial Matrix: [1000001000001000001000001][10242101029420042014400051]
Using some row transformations we convert this initial matrix into LU factorization,
where L will the matrix having all diagonal entries 1, and entries above diagonal 0.
Step 2
by some row transformations, we get the matrix L and matrix U
L=[1000011000001000151310100005151]
U=[10242100568004200050000]
If we multiply L and U, we will get the same matrix A.
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