(4x^2 − x − 23) / (x-1) Use polynomial long division to perform the indicated division. Write the polynomial in the form p(x) = d(x)q(x) + r(x)

Step 1
Consider the division ${\displaystyle \frac{4x^2-x-23}{x-1}}$.
Here, the dividend is ${\displaystyle 4x^2-x-23}$ and the divisor is x-1.
${\displaystyle \frac{4x+3}{x}-1)4x^2-x-23}$
${\displaystyle \frac{4x^2-4x}{3x-23}}$
${\displaystyle \frac{3x-3}{-20}}$
Step 2
Write the result in the form of p(x) = d(x)q(x) + r(x) as follows.
${\displaystyle 4x^2-x-23=(x-1)(4x+3)+(-20)}$
=(x-1)(4x+3)-20
Step 3
Answer:
The polynomial in the form of ${\displaystyle p\left(x\right)=d\left(x\right)q\left(x\right)+r\left(x\right)\text{ is }4x^2-x-23=(x-1)(4x+3)-20}$.