# Solve the qudaratic equation by factorization x^2+x-(a+1)(a+2)=0

Solve the qudaratic equation by factorization
${x}^{2}+x-\left(a+1\right)\left(a+2\right)=0$
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Liyana Mansell
Step 1
Given:
$⇒{x}^{2}+x-\left(a+1\right)\left(a+2\right)=0$
Step 2
$⇒{x}^{2}+x-\left(a+1\right)\left(a+2\right)=0$
$⇒{x}^{2}=x\left(a+2\right)-x\left(a+1\right)-\left(a+1\right)\left(a+2\right)=0$
$⇒x\left(x+a+2\right)-\left(a+1\right)\left(x+a+2\right)=0$
$⇒\left(x-a-1\right)\left(x+a+2\right)=0$
$⇒x-a-1=0$ and x+a+2=0
$⇒x=a+1,-a-2$