How do I show (\csc \theta-\cot \theta)^2 \equiv \frac{1-\cos \theta}{1+\cos

Lainey Goodwin

Lainey Goodwin

Answered question

2022-01-25

How do I show (cscθcotθ)21cosθ1+cosθ?

Answer & Explanation

portafilses

portafilses

Beginner2022-01-26Added 13 answers

There is
(cscθcotθ)2=(1sinθcosθsinθ)2=(1cosθsinθ)2
Since
sin2θ=1cos2θ
the expression becomes:
(cscθcotθ)21cosθ1+cosθ
and the identity is verified
Deegan Mullen

Deegan Mullen

Beginner2022-01-27Added 12 answers

csc2tcot2t=1cos2tsin2t=tant  for  sint0
1cos2t1+cos2t=2sin2t2cos2t=?

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