Solve by factorization a/(ax-1)+b/(bx-1)=a+b

babeeb0oL 2021-02-09 Answered
Solve by factorization
aax1+bbx1=a+b
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

Jozlyn
Answered 2021-02-10 Author has 85 answers
Step 1: Given,
The expression aax1+bbx1=a+b. We have to solve this by factorization.
Step 2: Calculation
aax1+bbx1=a+b
a(bx1)+b(ax1)(ax1)(bx1)=a+b
abxa+abxb(ax1)(bx1)=a+b
2abx(a+b)(ax1)(bx1)=a+b
2abx(a+b)=(a+b)(ax1)(bx1)
2abx(a+b)=(a+b)(abx2axbx+1)
(a+b)abx2(a+b)2x+(a+b)2abx+(a+b)=0
(a+b)abx2[(a+b)22ab]x+2(a+b)=0
If we have a quadratic equation ax2+bx+c=0thenx=b±b24ac2a
From the equation (a+b)abx2a+b22abx+2a+b=0 we have
x=[(a+b)22ab]±[(a+b)22ab]28ab(a+b)22ab(a+b)

We have step-by-step solutions for your answer!

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

New questions