Solve by factorization 6x^2+x-2=0

Maiclubk 2021-02-02 Answered
Solve by factorization
6x2+x2=0
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Expert Answer

grbavit
Answered 2021-02-03 Author has 109 answers
Step 1
factor the following 6x2+x2=0
Step 2
Factor the quadratic 6x2+x2
The coefficient of x2 is 6 and the constant term is −2.
The product of 6 and −2 is −12. The factors of −12 which sum to
1 are −3 and 4
So 6x2+x2=6x2+4x3x2=2(2x1)+3x(2x1):
2(2x−1)+3x(2x−1):
Factor 2x−1 from 2(2x−1)+3x(2x−1)=(2x−1)(3x+2),
=(2x−1)(3x+2)
Now set (2x−1)(3x+2)=0
(2x−1)=0 and (3x+2)=0
x=12andx=23
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