# Find the zeroes of the polynomial by factorization method 3x^2+4x-4

Find the zeroes of the polynomial by factorization method
$3{x}^{2}+4x-4$
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Step 1
Given
$3{x}^{2}+4x-4$
Step 2 By factorization
$3{x}^{2}+6x-2x-4$
$3x\left(x+2\right)-2\left(x+2\right)$
$\left(x+2\right)\left(3x-2\right)=0$
$x+2=0,3x-2=0$
$x=-2,3x=2$
$x=\frac{2}{3}$
$\therefore$ Zeroes are $\frac{2}{3}$ and -2

Jeffrey Jordon