Question

Find the zeroes of the polynomial by factorization method
\(\displaystyle{3}{x}^{{2}}+{4}{x}-{4}\)

Answer 1

Step 1
Given
\(\displaystyle{3}{x}^{{2}}+{4}{x}-{4}\)
Step 2 By factorization
\(\displaystyle{3}{x}^{{2}}+{6}{x}-{2}{x}-{4}\)
3x(x+2)-2(x+2)
(x+2)(3x-2)=0
x+2=0, 3x-2=0
x=-2, 3x=2
\(\displaystyle{x}=\frac{{2}}{{3}}\)
\(\displaystyle\therefore\) Zeroes are \(\displaystyle\frac{{2}}{{3}}\) and -2