# Solving 2\sin(x+30^{\circ})=\cos(x+150^{\circ}) for x between 0^{\circ} \text{ and } 360^{\circ}

Solving $2\mathrm{sin}\left(x+{30}^{\circ }\right)=\mathrm{cos}\left(x+{150}^{\circ }\right)$ for x between
You can still ask an expert for help

## Want to know more about Trigonometry?

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

spelkw
HINT
The equation is equivalent to
$2\mathrm{sin}x{\mathrm{cos}30}^{\circ }+2{\mathrm{sin}30}^{\circ }\mathrm{cos}x=\mathrm{cos}x{\mathrm{cos}150}^{\circ }-\mathrm{sin}x{\mathrm{sin}150}^{\circ }$
$\sqrt{3}\mathrm{sin}x+\mathrm{cos}x=-\frac{\sqrt{3}}{2}\mathrm{cos}x-\frac{12}{\mathrm{sin}x}$