Consider the given function,
differentiate the function with respect to x,
for the maxima and minima, f′(x)=0,
the values of x lie in the interval is,
Now, use the second derivative test so differentiate again,
at x = 0,
so, the function has the absolute maximum at x=0,
now, for the absolute maximum value substitute x=0 in the function,
the absolute maximum value of the function is 11.
so, the function has the absolute minimum at x=4,
now, for the absolute minimum value substitute x=4 in the function,
the absolute minimum value of the function is −245.
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