I am overthinking this but (-4)^{(-5/2)} is not a valid

Jayleen Sanders 2022-01-22 Answered
I am overthinking this but (4)(52) is not a valid equation, am I correct? Working through the problem gives me 1452 which then works out to 145 which leaves a negative number in the square root, which is not valid.
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

Joy Compton
Answered 2022-01-23 Author has 13 answers
It is perfectly valid, the result is simply not a Real Number, it is what is called an Imaginary Number (or a Complex Number in the case in which you had a Real Numbered component as well), which you may not be familiar with.
The result you gave simplifies down to 132i, where i is called the Imaginary Unit, and is equal to 1
Not exactly what you’re looking for?
Ask My Question
gekraamdbk
Answered 2022-01-24 Author has 13 answers
The square root of a negative number is a complex number (4)52=145=1(2i)5=132i. If this sounds like complete gibberish to you, google "imaginary numbers" and read up on it.
Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

New questions