How do you solve 6y^{2}+y \pm 2=0?

Cassarrim1

Cassarrim1

Answered question

2022-01-20

How do you solve 6y2+y±2=0?

Answer & Explanation

Deegan Mullen

Deegan Mullen

Beginner2022-01-21Added 12 answers

You simply need to solve the two equations: one with the plus sign, and the other with the minus sign.
- Interpreting ±as +: the equation becomes 6y2+y+2=0. The discriminant of 6y2+y+2 is negative, and so there are no solutions.
- Interpreting ±as : the equation becomes 6y2+y2=0. The discriminant of 6y2+y2 is positive. So we can solve it, using the formula
y1,2=b±b24ac2a
Since a=6,b=1 and c=2, the formula becomes
y1,2=1±4912=1±712
So, y1=1712=812=23,and y2=1+712=612=12

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