# How do you solve 8y^{2}-9y=-1?

How do you solve $8{y}^{2}-9y=-1?$
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Step 1 Express in standard form; $a{x}^{2}+bx+c=0$ $8{y}^{2}-9y+1=0$ using the a-c method to factor the quadratic the factors of the product $8×1=8$ which sum to -9 are -8 and -1 split the middle term using these factors $8{y}^{2}-8y-y+1=0←$ factor by grouping $8y\left(y-1\right)-1\left(y-1\right)=\right)$ take out the common factor $\left(y-1\right)$ $\left(y-1\right)\left(8y-1\right)=0$ equate each factor to zero and solve for y $8y-1=0⇒y=\frac{1}{8}$ $y-1=0⇒y=1$