How do you solve $8{y}^{2}-9y=-1?$

elbluffz1
2022-01-23
Answered

How do you solve $8{y}^{2}-9y=-1?$

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Georgia Ingram

Answered 2022-01-24
Author has **11** answers

Step 1

So there are several ways to go about this:

The first thing Im

So there are several ways to go about this:

The first thing Im

sineurosi0f

Answered 2022-01-25
Author has **14** answers

Step 1

If factoring doesnt

If factoring doesnt

RizerMix

Answered 2022-01-27
Author has **438** answers

Step 1
Express in standard form; $a{x}^{2}+bx+c=0$
$8{y}^{2}-9y+1=0$
using the a-c method to factor the quadratic
the factors of the product $8\times 1=8$
which sum to -9 are -8 and -1
split the middle term using these factors
$8{y}^{2}-8y-y+1=0\leftarrow $ factor by grouping
$8y(y-1)-1(y-1)=)$
take out the common factor $(y-1)$
$(y-1)(8y-1)=0$
equate each factor to zero and solve for y
$8y-1=0\Rightarrow y=\frac{1}{8}$
$y-1=0\Rightarrow y=1$

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